Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The reaction of nitrogen with hydrogen to make ammonia has Δ H = – 92 kJ
N 2 (g) + 3H 2 (g) ⎯→ 2NH 3 (g)
What is the value of Δ U (in kJ) if the reaction is carried out at a constant pressure of 40 bar and the volume change is – 1.25 litre.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(–87 )
Δ U = Δ U + 40 × (– 1.25) × 100
Δ U = – 92+ 5
Δ U = – 87 kJ.
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