In 1 L saturated solution of AgCl [K sp (AgCl) = 1.6 × 10 –10 ], 0.1 mole of CuCl [K sp (CuCl) = 1.0 × 10 –6 ] is added. The resultant concentation of Ag + in the solution is 1.6 × 10 –x . The value of "x" is :
Text Solution
Verified by Experts7
(7)
Sol. AgCl (s) 
Ag + + Cl – K sp (AgCl) = 1.6 × 10 –10
Z Z + Y
CuCl (s) 
Cu + + Cl – K sp (CuCl) = 10 –6
Y Z + Y
Z (Z + Y) = 1.6 × 10 –10 and Y (Z + Y) = 10 –6
⇒ (Z + Y) 2 = 1.6 × 10 –10 + 10 –6
⇒ (Z + Y) 2 ≈ 10 –6
⇒ Z + Y = 10 –3
We know
⇒ Z (Z + Y) = 1.6 × 10 –10
⇒ Z × 10 –3 = 1.6 × 10 –10
⇒ Z = 1.6 × 10 –7
⇒ 1.6 × 10 –x = 1.6 × 10 –7
⇒ x = 7
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems