Published by:
CGP EDU Academic Team
Published on: August 14, 2026
In a 3.24 L closed cylindrical container, the following equilibrium is established at 0ºC :
2Ag(s) + 2 I – (aq) + 2H 2 O( λ ) 
2Ag I (s) + H 2 (g) + 2OH – (aq)
The equilibrium constant for the above reaction is 4 × 10 –9 . At equilibrium, solution occupies 
height of the container and contains 0.5 M I – and other species. If gaseous matter weighs 2 g, find pOH of solution. Neglect aqueous tension.
Text Solution
Verified by ExpertsThe correct answer is:
5
(5)
Sol. 
= 10 atm (as 1 mole H 2 in 2.24 L at 0ºC) & [ I – ] = 0.5 M
K = 
⇒ [OH – ] 2 = 
⇒ [OH – ] = 10 –5 M ∴ pOH = 5
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