Published by:
CGP EDU Academic Team
Published on: August 14, 2026
EMF of the following cell is 0.634 volt at 298 K Pt | H 2 (1 atm) | H + (aq) || Hg 2 2+ (aq.,1N) | Hg( λ ). The pH of anode compartment is :
Given 
= 0.28 V and 
= 0.059
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
6
Sol. At cathode : 
Hg 2 2+ + e – 
Hg(l)
At anode : 
H 2 (g) 
H + (aq) + e –
Hg 2 2+ + 
H 2 (g) 
Hg(l) + H + (aq)
E cell = 
– 
log [H + ]
or 0.634 = (0.28 – 0) + 0.059 pH
or pH = 
= 6
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