Published by:
CGP EDU Academic Team
Published on: August 14, 2026
On introducing a catalyst at 500 K, the rate of a first order increase to 1.718 times. The activation energy in the presence of a catalyst is 6.05 KJ/mole. The slope of the plot of lnk (sec –1 ) against 1/T in the absence of catalyst is.
Text Solution
Verified by ExpertsThe correct answer is:
1
1000
Sol. 1.718 = Antilog = 
E a – E p = 2.25 KJ
E a = E p + 2.25 = 6.05 + 2.25 = 8.30 KJ/mole
lnk = lnA – 
Slope = 
= 
= – 1000
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Which of these does not influence the rate of reaction
The rate law for reaction will be
In the reaction , initial pressure is and rate constant is . After 10 minutes the final pressur…
The rate law for the reaction
Sucrose + Water Glucose + Fructose is given by
. If 1, then is
The data for the reaction is
Exp.Initial rate(1)0.0120.0350.10(2)0.0240.0700.80(3)0.0240.0350.10(4…