Calculate the molality and molarity of a solution made by mixing equal volumes of 30% by weight of H 2 SO 4 (density = 1.20 g/mL) and 70% by weight of H 2 SO 4 (density = 1.60 g/mL).
Text Solution
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Molality = 11.44 m, Molarity = 7.55 M
Suppose that the solution contains 100 ml of each variety of H 2 SO 4 . Total solution is, 200 ml or 0.2 litre
wt. of 100 ml of H 2 SO 4 solution (30%) = 1.20 × 100 = 120 gram
and wt. of 100 ml of H 2 SO 4 solution (70%) = 1.60 × 100 = 160 gram
wt. of H 2 SO 4 (30%) = 120 × 
= 36 gram
wt. of H 2 SO 4 (70%) = 160 × 
= 112 gram
Total wt. of H 2 SO 4 (solute) = 36 + 112 = 148 gram
∴ wt. of H 2 O (solvent) = wt. of solution – wt. of solute
= (120 + 160) – 148 = 280 – 148 = 132 gram
Moles of H 2 SO 4 = 
= 1.51 (mol. wt. of H 2 SO 4 = 98)
Molality = 
× 1000 = 11.44 m
Molarity = 
= 7.55 M
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