A mixture of an organic liquid A and water distilled under one atmospheric pressure at 99.2ºC. How many grams of steam will be condensed to obtain 1.0 g of liquid A in the distillate ? (Vapour pressure of water at 99.2ºC is 739 mm Hg. Molecular weight of A = 123)
Text Solution
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(5.15 g)
When the liquid A-water mixture distills, the pressure = 760 mm Hg.
∴ Partial pressure of A = 760 – 739 = 21 mm Hg.
Mole fraction of A in the distillate = 
= 0.02764
Mole fraction of water in the distillate = 
= 0.9723
∴ mass of A in the distillate = 0.02764 × 123 = 3.399 g
Mass of water in the distillate = 0.9723 × 18 = 17.50 g
Mass of steam condensed per g of liquid A = 
= 5.15 g.
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