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CGP EDU Academic Team
Published on: August 14, 2026
Twenty grams of a solute are added to 100 g of water at 25ºC. The vapour pressure of pure water is 23.76 mmHg; the vapour pressure of the solution is 22.41 Torr.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
60 g/mol , 333.3g
Relative lowering of vapour pressure = mole fraction of solute
= 
= 0.0568
so M = 60 g/mol
Let w be the mass of solute reqd.
& P = 
so 
= 
or 
= 
∴ w = 333.3 g
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