Published by:
CGP EDU Academic Team
Published on: August 14, 2026
An ideal solution contains two volatile liquids A (pº = 100 torr) and B (pº = 200 torr). If mixture contain 1 mole of A and 4 mole of B then total vapour pressure of the distillate is:
Text Solution
Verified by ExpertsThe correct answer is:
C
P = P A º x A + P B º x B
⇒ 100 × 
⇒ 180 torr
y A (composition of A in vapour phase) = 
⇒
⇒
, Y B = 
For condensation y A = x 1 A ; y B = x 1 B
P total = P A º x A 1 + P B º x B 1 ;
P total = 100 ×
× 200 ⇒ 188.88 torr
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
On adding solute to a solvent having vapour pressure 0.80 atm , vapour pressure reduces to 0.60 atm…
A solution containing 30 gms of non-volatile solute in exactly 90 gm water has a vapour pressure of…
Vapour pressure of a solution of of non- electrolyte in of water at a particular temperature is …
Azeotropic mixture of HCl and water has
The osmotic pressure at of an aqueous solution containing 1.75 g of sucrose per 150 ml solution is
A 1.2 of solution of NaCl is isotonic with 7.2 of solution of glucose. Calculate the van’t Hoff’s f…