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CGP EDU Academic Team
Published on: August 14, 2026
At 27ºC, a 1.2% solution ( wt./vol.) of glucose is isotonic with 4.0 g/litre of solution of solute X. Find the molar mass of X, if the molar mass of glucose is 180. (R = 0.082 L atm mol –1 K –1 , Molar mass of glucose = 180 g/mole)
Text Solution
Verified by ExpertsThe correct answer is:
60
(60)
1.2% solution (wt./vol) of glucose is isotonic with 4 g/litre of solution of X at 27ºC, so
C 1 = C 2
so M X = 60 g/mole.
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