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CGP EDU Academic Team
Published on: August 14, 2026
For a dilute solution containing 2.5 g of a non- volatile non- electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2ºC. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take K b = 0.76 K kg mol –1 )
Text Solution
Verified by ExpertsThe correct answer is:
A
Δ T b = 2ºC; m a = 2.5 g
m solvent = 100 g
K b = 0.76 K. kg. mol –1
P solution = ?
Δ T b = K b × m
2 = 0.76 × m ∴ m = 
= m × MM × 10 –3 ∴ 
= 
× 18 × 10 –3
760 – P = 
∴ 760 = 
∴ P = 760 
torr = 725.6 torr 
724 torr
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