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CGP EDU Academic Team
Published on: August 13, 2026
In a FCC lattice of a metal edge length is 400 pm. Find the maximum diameter of an atom which can be accommodated in an interstitial gap in this lattice without causing any distortion.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(117.08 pm)
Sol. For f.c.c. 
octahedral void
= 0.225 tetrahedral void
We know along face diagonal for f.c.c. 4r 2 = a 
⇒ r 2 = 
Required diameter of interstitial sites = 2r 1 = 2 × 0.414r 2
Diameter = 
= 
= 117.1 pm.
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