Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The density of solid argon is 1.65 g/mL at – 233ºC. If the argon atom is assumed to be sphere of radius 1.54 × 10 –8 cm, what percentage of solid argon is apparently empty space ? (At. wt. of Ar = 40)
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
62
Sol. Volume of one atom of Ar = 
π r 3
Also, number of atoms in 1.65 g or one mL = 
× 6.023 × 10 23
∴ Total volume of all atoms of Ar in solid state
= 
π r 3 × 
× 6.023 × 10 23 = 
× 
× (1.54 × 10 –8 ) 3 × 
× 6.023 × 10 23 = 0.380 cm 3
Volume of solid argon = 1 cm 3
∴ % empty space = 
× 100 = 62%
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