Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The standard oxidation potential of Zn referred to SHE is 0.76V and that of Cu is –0.34V at 25ºC. When excess of Zn is added to CuSO 4 , Zn displaces Cu 2+ till equilibrium is reached. What is the approx value of log 
at equilibrium?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
log [Zn 2+ ] / [Cu 2+ ] = 37.22
Sol. Eº Zn / Zn2+ = 0.76 volt Eº Cu / Cu2+ = – 0.34 volt
CuSO 4 + Zn 
ZnSO 4 + Cu.
O = (0.76 + 0.34) – 
log 
= 37.22
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