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CGP EDU Academic Team
Published on: August 13, 2026
A fuel cell uses CH 4 (g) and forms CO 3 2– at the anode. It is used to power a car with 80 Amp. for 0.96 hr. How many litres of CH 4 (g) (STP) would be required ? (V m = 22.4 L/mol) (F = 96500). Assume 100% efficiency.
Text Solution
Verified by ExpertsThe correct answer is:
8
(8)
Sol. CH 4 + 10OH¯
CO 3 2– + 7H 2 O + 8e –
No. of Faradays required = 
Hence mol. of CH 4 required =
x 
=
x
x 22.4 L = 8.356 x 0.96 = 8.02 L Ans. 8
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