H 4 XeO 6 + 2H + + 2e – ⎯→ XeO 3 + 3H 2 O Eº = 3 V
F 2 + 2e – ⎯→ 2F – Eº = 2.87 V
O 3 + 2H + + 2e – ⎯→ O 2 + H 2 O Eº = 2.07 V
Ce 4+ + e – ⎯→ Ce 3+ Eº = 1.67 V
2HClO + 2H + + 2e – ⎯→ Cl 2 + 2H 2 O Eº = 1.63 V
+ 2H + + 2e – ⎯→ 
+ H 2 O Eº = 1.23 V
ClO – + H 2 O + 2e – ⎯→ Cl¯ + 2OH – Eº = 0.89 V
BrO – + H 2 O + 2e – ⎯→ Br¯ + 2OH – Eº = 0.76 V
+ H 2 O + 2e – ⎯→ 
+ 2OH – Eº = 0.36 V
[Fe(CN) 6 ] 3– + e – ⎯→ [Fe(CN) 6 ] 4– Eº = 0.36 V
Based on the above data, how many of the following statements are correct ?
is better oxidizing agent in basic medium than in acidic medium
in basic medium (f) Ce 4+ can oxidize Cl 2 in acidic medium under standard conditions.
Text Solution
Verified by ExpertsC
3 (B, E & F)
Sol. H 4 XeO 6 has more SRP, so better oxidizing agent then F 2
O 3 has more SRP, so will oxidize Cl 2
is more in acidic medium than in basic medium
= 0.36 V
Hence [Fe(CN) 6 ] 4– can be easily oxidized by ClO¯, Ce 4+ Br 2 O – but not by Li +
(e) 
is more than 
and 
so true.
(f) Ce 4+ can’t oxidize Cl 2 in acidic medium.
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