When a lead storage battery is discharged then
Text Solution
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(b,c,d) Anode : Pb(s)
Cathode : PbO 2 (s)
H 2 SO 4 (conc.) about 38% solution of H 2 SO 4 is taken.
Anode : Pb(s) ⎯→ Pb 2+ (aq) + 2e –
Pb 2+ (aq) + 
(aq) ⎯→ PbSO 4 (s)
Pb(s) + 
(aq) ⎯→ PbSO 4 + 2e –
most of the PbSO 4 (s) ppt sticks to the lead rod.
Cathode : 2e – + 4H + + PbO 2 (s) ⎯→ Pb 2+ (aq) + 2H 2 O( λ )
Pb 2+ (aq) + 
(aq) +4H + + 2e – ⎯→ PbSO 4 (s) + 2H 2 O( λ )
PbSO 4 (s) sticks to cathode rod.
Over all reaction : Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) ⎯→ 2PbSO 4 (s) + 2H 2 O( λ ), E cell = 2.05 V
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