The conductance of a 0.0015 M aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized Pt electrodes. The distance between the electrodes is 120 cm with an area of cross section of 1 cm 2 . The conductance of this solution was found to be 5 × 10 –7 S. The pH of the solution is 4. The value of limiting molar conductivity ( Λ º m ) of this weak monobasic acid in aqueous solution is Z × 10 2 S cm –1 mol –1 . The value of Z is
Text Solution
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6
Sol. C = 0.0015M λ = 120 cm
G = 5 × 10 –7 s a = 1 cm 2
G = κ × 
5 × 10 –7 = κ × 
κ = 6 × 10 –5 s cm –1
= 
= 
pH = 4
[H + ] = 10 –4 = c α = 0.0015 α
α = 
α = 
⇒ ⇒ 
= 
= 6 × 10 2 s cm 2 mole –1
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