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CGP EDU Academic Team
Published on: August 14, 2026
The mass of copper deposited when a current of 10A is passed through a solution of copper(II) nitrate for 30.6s is
Text Solution
Verified by ExpertsThe correct answer is:
A
charge passed = 30.6 × 10 = 306 C
Faraday Passed = 
= 0.003
gram equivalent of Cu formed = 3 × 10 -3
= 3 × 10 –3
E Cu = 63.5/2
W = 31.75 × 10 –3 × 3 = 0.09525
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