Three Faradays of electricity are passed through aqueous solutions of AgNO 3 , NiSO 4 and CrCl 3 kept in three vessels using inert electrodes. The ratio (in moles) in which the metals Ag, Ni and Cr are deposited is
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AgNO 3 , NiSO 4 , CrCl 3
AgNO 3 → Ag + + 
↓
Ag (requires 1 mole electron i.e. 1 Farad charge.)
NiSO 4 → Ni 2+ + 
↓
Ni (requires 2 mole electron i.e. 2 Farad charge.)
CrCl 3 → Cr 3+ + 3Cl –
↓
Cr (requires 3 mole electron i.e. 3 Farad charge.)
But the charge passed is 3F.
3F charge deposit 1 mole Cr 3+ } ….
⇒ Ag : Ni : Cr = 3 : 
: 1 ⇒ 6 : 3 : 2
Correct option is .
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