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CGP EDU Academic Team
Published on: August 13, 2026
Find the sum of number of geometrical isomers for following complexes.
Text Solution
Verified by ExpertsThe correct answer is:
D
4 (0 + 0 + 2 + 0 + 2 = 4)
Sol. For CoCl 2 Br 2 → No. of G.I. = 0
For [Rh(en) 3 ] 3+ → No. of G.I. = 0
For [Cr(en) 2 Br 2 ] + → No. of G.I. = 2
For [Pt (en) Cl 2 ] → No. of G.I. = 0
For [Co(NH 3 ) 3 (NO 2 ) 3 ] → No. of G.I. = 2
Hence sum of Geometrical isomers = 4.
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