A green complex, K 2 [Cr(NO)(NH 3 )(CN) 4 ] is paramagnetic and has μ eff = 1.73 BM. Write the IUPAC name of the complex and draw the structure of anion and find out the hybridisation of metal ion
Text Solution
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IUPAC name is :
Potassium amminetatracyanidonitrosoniumchromate(I)
or Potassium amminetatracyanidonitrocyliumchromate(I).
Let n is the number of unpaired electron in the chromium ion.
Since μ = 
or 1.73 = 
B.M. or 1.73 × 1.73 = n 2 + 2n.
Hence n = 1.
As the CN – and NH 3 are strong fields ligands, they compel for pairing of electrons. So,
[Cr(NO)(CN) 4 (NH 3 )] 2– = 
Hence, the oxidation state of chromium is +1 (having 3d 5 configuration). So according to charge on the complex NO should be NO + and the structure of this complex is octahedral with d 2 sp 3 hybridisation as given below
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