Consider the following statements
S 1 : [Cr(NH 3 ) 6 ] 3+ is a inner orbital complex with crystal field stabilization energy equal to –1.2 Δ o
S 2 : The complex formed by joining the CN – ligands to Fe 3+ ion has theoretical value of ‘spin only’ magnetic moment equal to 1.73 B.M.
S 3 : Na 2 S + Na 2 [Fe(CN) 5 NO] 
Na 4 [Fe(CN) 5 NOS], In reactant and product the oxidation states of iron are same and arrange in the order of true/false.
Text Solution
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S 1 : Cr 3+ 
CFSE = 3 × – 0.4 = – 1.2 Δ 0 , hybridisation is d 2 sp 3 (NH 3 is strong field ligand)
S 2 : Fe 3+ , 3d 5 - one unpaired electron after pairing (CN – is stronger field ligand)
∴ μ = 
≈ 1.73 BM
S 3 : 
and 
.
In reactant and product, the iron is in same oxidation state i.e. +2.
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