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CGP EDU Academic Team
Published on: August 13, 2026
The number of chloride ions which would be precipitated when one mole of the complex PtCl 4 .4NH 3 is treated with silver nitrate is: (here coordination number of platinum is 6).
Text Solution
Verified by ExpertsThe correct answer is:
D
PtCl 4 .4NH 3 ≡ [Pt(NH 3 ) 4 Cl 2 ]Cl 2 
[Pt(NH 3 ) 4 Cl 2 ] 2+ (aq) + 2Cl – (aq).
2Ag + + 2Cl – ⎯→ 2AgCl ↓ (white)
Concentrated H 2 SO 4 will not dehydrate the following complex.
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