The Total pressure observed by mixing two liquid A and B is 350 mm Hg when their mole fractions are 0.7 and 0.3 respectively.
The Total pressure becomes 410 mm Hg if the mole fractions are changed to 0.2 and 0.8 respectively for A and B. The vapour pressure of pure A is______mm Hg. (Nearest integer)Consider the liquids and solutions behave ideally,
Text Solution
Verified by Experts314
(314)
Let V.P. of pure A be 
Let V.P of pure B be 
When X A =0.7 &X B =0.3
P s = 350
x0.7 + 
x0.3 = 350 ...(i)
When X A =0.2&X B =0.8
P s =410
x0.2 + 
x0.8 = 410 ...(ii)
Solving (i) and (ii)
=314mmHg
= 434 mm Hg
=(314)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems