Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15°C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at -0.8° C The solutbility product of PbCl 2 formed is______x 10 -6 at 298 K. (Nearest integer)
Given : K b = 0.5 K kg mol -1 and K f = 1.8 kg mol -1 .
Assume molality to be equal to molarity in all cases.
Text Solution
Verified by ExpertsThe correct answer is:
13
(13)
Let a mole Pb(NO 3 ) 2 be added
t=0 0.1 0.2
(0.1-x) (0.2-2x)
In final solution
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