Home Chemistry Thermodynamics and Thermochemistry JEE Main 2023 An athlete is given 100 g of glucose (C 6 H …
Chemistry Thermodynamics and Thermochemistry JEE Main 2023 Numeric Response
Published on: August 14, 2026

An athlete is given 100 g of glucose (C 6 H 12 O 6 ) for energy. This is equivalent to 1800 kJ of energy. The 50% of this energy gained is utilized by the athlete for sports activities at the event. In order to avoid storage of energy, the weight of extra water he would need to perspire is_______g (Nearest integer)

Assume that there is no other way of consuming stored energy.

Given : The enthalpy of evaporation of water is 45 kJ mol -1

Molar mass of C, H & O are 12. 1 and 16 g mol -1 .

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The correct answer is:
360

(360)

C 6 H 12 O 6 (s) + 6O 2 6CO 2 (g) + 6H 2 O(a)

Extra energy used to convert H 2 O(a) into H 2 O(a) into H 2 O(g)

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