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CGP EDU Academic Team
Published on: August 14, 2026
1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. The work done is 3 kJ mol -1 . The final temperature of the gas is _______K (Nearest integer). Given C v =20 J mol -1 K -1 ,
Text Solution
Verified by ExpertsThe correct answer is:
150
(150)
q = 0
U= w
1x20x[T 2 -300]=-3000
T 2 - 300 = - 150
T 2 = 150 K
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