The total change in the oxidation state of manganese involved in the reaction of KMnO 4 and potassium iodide in the acidic medium is________.
Text Solution
Verified by Experts5
(5)
In the reaction of KMnO 4 and potassium iodide (KI) in an acidic medium, the KMnO 4 acts as an oxidizing agent, and the iodide ions (I - ) in KI act as reducing agents.
KMnO 4 + KI + H + 
Mn +2 + I 2 + H 2 O
In KMnO 4 , the oxidation state of manganese is +7, which is the highest possible oxidation state for manganese in this compound.
In the final product, MnSO 4 , the oxidation state of manganese is +2.
Therefore, the total change in the oxidation state of manganese is:
+7 (initial) - + 2 (final) = 5
Hence the change in O. S. of Mn is (5).
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