When only a little quantity of HgCl 2 (s) is added to excess KI(aq) to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing).
The reaction is 4KI(aq.) + HgCl 2 (s) → K 2 [HgI 4 ] (aq.) + 2KCl (aq.)
Text Solution
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Due to this addition a complex [HgI 4 ] 2– will get formed as follows
Hg 2+ + 4I – 
[HgI 4 ] 2– or Hg
2+ + 2Cl – + 4I – 
[HgI 4 ] 2– + 2Cl – on adding we can see that 4I
– ions are consumed but resultant number of particles are three. Hence boiling point gets decreased. Freezing point gets increased.
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