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CGP EDU Academic Team
Published on: August 14, 2026
The Henry's law constant for the solubility of N 2 gas in water at 298 K is 1.0 × 10 5 atm. The mole fraction of N 2 in air is 0.8. The number of moles of N 2 from air dissolved in 10 moles of water of 298 K and 5 atm pressure is:
Text Solution
Verified by ExpertsThe correct answer is:
A
P N2 = K H × 
= 
× 0.8 × 5 = 4 × 10 –5 per mole
In 10 mole solubility is 4 × 10 –4 .
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