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Published on: August 14, 2026
Δ H o f of water is – 285.5 kJ mol –1 . if enthalpy of neutralization of monoacidic strong base with strong acid is – 57.3 kJ mol –1 , Δ H f o of OH – ion will be
Text Solution
Verified by ExpertsThe correct answer is:
A
H + (aq) + OH – (aq) ⎯→ H 2 O( λ )
so Δ H° = – 57.3 = – 285.5 – Δ H f ° (H+, aq) – Δ H f ° (OH – , aq)
so Δ H f ° (OH – , aq) = – 228.5 kJ/mole (as Δ H f ° (H+, aq) = 0)
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