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CGP EDU Academic Team
Published on: August 13, 2026
Benzene burns according to the following equation at 300 K (R = 25/3 J mole –1 K –1 )
2C 6 H 6 ( λ ) + 15 O 2 (g) ⎯→ 12 CO 2 (g) + 6H 2 O( λ ) Δ H o = – 6547.5 KJ
What is the Δ E o for the combustion of 1.5 mol of benzene
Text Solution
Verified by ExpertsThe correct answer is:
C
From given reaction Δ n g = 12 – 15 = – 3
so Δ E° = Δ H° – Δ n g RT = – 6542 + 3RT
for 1.5 mole, Δ E° = 
{ –6542 + 3RT} = 4900.9 kJ
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