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Chemistry Chemical Kinetics JEE Main 2026 Numeric Response
Published on: August 13, 2026

The temperature at which the rate constants of the given below two gaseous reactions become equal is K. (Nearest integer)

Given:

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Verified by Experts
The correct answer is:
1303

(1303)

To find the temperature at which ,
set the rate constant equations equal: .
Dividing both sides by .
Taking natural logarithm: .
Since .
Solving for T: .
Rounding to the nearest integer gives .

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