A particle floats on the surface of a liquid of depth 4 cm and refractive index
. The bottom of the container is a concave mirror with a radius of curvature of 10 cm. What is the apparent position of the final image, as seen by an observer in the air directly above, after light rays from the particle first travel down, reflect off the mirror, and then travel up to refract at the liquid-air surface?

Text Solution
Verified by ExpertsC
Using the mirror formula: 
Here,
(object is in front of the mirror) and
.


So,
.
Apparent Depth
Real Depth × 
Here, the observer is in air
(
) and the object is in
liquid 
Apparent Depth

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