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CGP EDU Academic Team
Published on: August 13, 2026
If both roots of the equation x 2 – 6ax + 2 –2a + 9a 2 = 0, exceed 3, then a is-
Text Solution
Verified by ExpertsThe correct answer is:
D
(i) D ≥ 0 (ii) (1) f(3) > 0 (iii) 
> 3
(i) 36a 2 – 4(2 –2a + 9a 2 ) ≥ 0
a ≥ 1 …(i)
(ii) (1) (9 – 18a + 2 – 2a + 9a 2 ) > 0 (9a – 11) (a –1) > 0
a ∈ (– ∞ , 1) ∪ (11/9, ∞ ) … (ii)
(iii) 
> 3 a > 1 … (iii)
so, from (i), (ii) and (iii) a > 11/9
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