Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If (5 + 2 
) n = I + f ; n , I ∈ N; and 0 ≤ f < 1, then I equals-
A
–f
B
–f
C
+f
D
–f
Text Solution
Verified by ExpertsThe correct answer is:
D
Let f ′ = (5 –2 
) n
So, I + f + f ′ = (5 + 2 
) n + (5 –2 
) n = an integer
⇒ f + f ′ = 1 …(1)
Now, (I + f) × f ′ = (5 + 2 
) n (5 –2 
) n = 1
∴ I = 
–f = 
–f
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