Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Integral part of (5 
+ 11) 2n+1 is
Text Solution
Verified by ExpertsThe correct answer is:
A
(5 
+ 11) 2n+1 = I + f & let (5 
–11) 2n+1 = f ′
Also I + f –f ′ = (5 
+ 11) 2n+1 – (5 
–11) 2n+1 = 2 (integer)
= Even integer
Hence f –f ′ = 2k – I is an integer
But –1 < f – f ′ < 1, therefore f – f ′ = 0
⇒ I = 2k = even integer
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