Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If P is a point on the altitude AD of the triangle ABC such that ∠ PBD = 
, then AP is equal to -
A
2a sin 
B
2b sin 
C
2c sin 
D
Text Solution
Verified by ExpertsThe correct answer is:
C
∠ BPA = 90 0 + 
, ∠ ABP = 
In Δ ABP (sine Rule)
= 
= 
⇒ AP = 
= 
⇒ AP = 2c sin 
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In a Δ ABC, if P,Q,R divide sides AB, BC, CA respectively in k : 1. If , then k equals
In a triangle ABC, cos A cos B + sin A sin B sin C = 1, then the triangle is -
In a triangle ABC, =
In a Δ ABC, if a, b, c and A are given, then there are two Δ ’s with third sides c 1 and c 2 , then…
In a triangle ABC, tan = , tan = , then –
If in a triangle ABC sines of angles A and B satisfy the
equation 4 x 2 – 2 x + 1 = 0, then cos (A…