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CGP EDU Academic Team
Published on: August 12, 2026
ABC, sinC + cosC + sin(2B + C) – cos(2B + C) = 2 
then
Δ ABC is -
Text Solution
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CHECK THE SOLUTION.
(b, c)
sin C+cos C + sin(2B + C) – cos (2B+C) = 2 
⇒ sin (2B + C) + sin C + cos C – cos (2B + C) = 2 
⇒ 2sin(B + C)cos B + 2sin (B + C) sin B = 2 
⇒ sin A (cos B + sin B) = 
⇒ sin A sin 
= 1
⇒ sinA = 1 and sin 
= 1
⇒ ∠ A = 90 0 & ∠ B = 45 0 then ∠ C = 45 0
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