Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If cos –1 p + cos –1 q + cos –1 r = π . Then value of p 2 + q 2 + r 2 + 2pqr + 4 is equal to-
Text Solution
Verified by ExpertsThe correct answer is:
C
Let cos –1 p = α , cos –1 q = β , cos –1 r = γ
cos α = p, cos β = q, cos γ = r , α + β + γ = π
cos ( α + β ) = cos ( π – γ )
⇒ cos α .cos β – sin α sin β = –cos γ
⇒ pq –
= – r
⇒ p 2 + q 2 + r 2 + 2pqr = 1
⇒ p 2 + q 2 + r 2 + 2pqr + 4 = 5.
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