Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Find all positive values of 'a' for which the equation log (ax) = 2 log (x + 1) has the unique root.
Text Solution
Verified by ExpertsThe correct answer is:
0004
Ans. 0004
Sol. log ax = 2 log (x + 1)
⇒ ax = (x + 1) 2 ⇒ x 2 + (2 –a) x + 1 = 0
Let x 1 and x 2 be roots
x 1 =
and
x 2 = 
For solution exists a 2 –4a ≥ 0
a ≥ 4, a ≤ 0
For positive values a ≥ 4
For a > 4, x 1 and x 2 are different
For a = 4, x 1 and x 2 are same
Hence a = 4.
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