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CGP EDU Academic Team
Published on: August 13, 2026
If a, b, c and d are four positive real numbers such that abcd = 1, the minimum value of (1 + a) (1 + b) (1 + c) (1 + d) is
Text Solution
Verified by ExpertsThe correct answer is:
C
1 + a ≥ 
{A.M. ≥ G.M.}
1 + b ≥ 
1 + c ≥ 
1 + d ≥ 
∴ (1 + a) (1 + b) (1 + c) (1 + d) ≥ 16 
= 16
∴ min. value = 16 (for a = b = c = d = 1)
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