One of the diameter of the circle circumscribing the rectangle ABCD is 4y = x + 7.
If A and B are the points (–3, 4) and (5, 4) respectively, then the area of rectangle is-
Text Solution
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First, we note that none of the points A (–3, 4) B(5, 4) lie on the diameter 4y = x + 7

Let E ( α, β ) be the centre of the circle,
then 4 β = α + 7 … (i)
Since ABCD is a rectangle |EA| = |EB| ⇒ EA 2 = EB 2
⇒ ( α + 3) 2 + ( β – 4) 2 = ( α –5) 2 + ( β –4) 2
⇒ 6 α + 9 = – 10 α + 25
⇒ α = 1, and from (i) β = 2
Now |AB| =
= 8 and |BD| = 2|EB| = 2
=4 
From right ∠ d Δ ABD, AD 2 = BD 2 –AB 2
= 80 –64 = 16
⇒ |AD| = 4,
∴ Area of the rectangle ABCD = |AB|. |AD|
= 8.4 = 32 sq. units.
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