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CGP EDU Academic Team
Published on: August 14, 2026
In a plane there are two families of lines y =x+r, y = –x+ r, where r ∈ {0, 1, 2, 3, 4}. The number of squares of diagonal of length 2 formed by these lines is/are greater than-
Text Solution
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(a, b)
Each family has parallel lines having distance between them as 
unit and both the families are perpendicular to each other, so to form a square of diagonal 2 units, lines of alternate pair are to be chosen.
Both the families has 3 such pairs. So, no. of squares possible = 3 × 3 = 9
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