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CGP EDU Academic Team
Published on: August 14, 2026
If normal at point P on parabola y 2 = 4ax, (a > 0) meet it again at Q is such a way that OQ is of minimum length where O is vertex of parabola, then Δ OPQ is
Text Solution
Verified by ExpertsThe correct answer is:
A
∴ Normal at P(t 1 ) meets at Q(t 2 )
t 2 = 
| t 2 | ≥ 
For minimum length of OQ, |t 2 | should be minimum
∴ i.e. | t 2 | = 
If t 2 = 
⇒ t 1 = 
Slope of OQ = 
= m 1 and of OQ = 
= m 2
∴ m 1 m 2 = –1 ∴ Δ OPQ is right angled triangle.
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