Published by:
CGP EDU Academic Team
Published on: August 12, 2026
The angle between the rectangular hyperbolas (y – mx) (my + x) = a 2 and (m 2 – 1) (y 2 – x 2 ) + 4mxy = b 2 is-
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
For first hyperbola
(y – mx) 
+ (my + x) 
= 0
(my + x + my – m 2 x) + y – mx – m 2 y – mx = 0
⇒ 
= 
= m 1
For second hyperbola
(m 2 – 1) 
+ 4m 
= 0
(2y (m 2 – 1) + 4 mx) = – 4my + 2x (m 2 – 1)
⇒ 
= 
= m 2 .
m 1 m 2 = –1 ⇒ Angle between the hyperbolas = 
.
Hence is correct answer.
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