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CGP EDU Academic Team
Published on: August 13, 2026
A rectangular hyperbola whose centre is C is cut by any circle of radius r in four points P, Q, R and S. then CP 2 + CQ 2 + CR 2 + CS 2 is equal to -
Text Solution
Verified by ExpertsThe correct answer is:
D
Let equation of the rectangular hyperbola be
xy = c 2 … (1)
and equation of circle be
x 2 + y 2 = r 2 … (2)
Put y =
in equation (2), we get
x 2 +
= r 2 ⇒ x 4 – r 2 x 2 + c 4 = 0 … (3)
Now, CP 2 + CQ 2 + CR 2 + CS 2 = 
=
– 2 Σ x 1 x 2 +
– 2 Σ y 1 y 2
= 2r
2 + 2r 2 = 4r 2 . [From (3)]
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