The points on the curve 5x 2 – 8xy + 5y 2 = 4 whose distance from the origin is maximum or minimum are -
Text Solution
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(a,b,c,d)
Let (r, θ ) be the polar co-ordinates of any point P on the curve where r is the distance of the point from origin
∴ r 2 [5 (cos 2 θ + sin 2 θ ) – 8 sin θ . cos θ ] = 4
∴ r 2 = 
r 2 is maximum when 5 – 4 sin 2 θ is minimum
= 5 – 4 = 1 when sin 2 θ = 1
∴ 2 θ = 90 0 ∴ θ = 45 0 ∴ r = ± 2, θ = 45
0 …(1)
Again r 2 is minimum when 5 – 4 sin 2 θ is maximum = 5 + 4 = 9 when sin 2 θ = –1
∴ 2 θ =
∴ θ = 
∴ r = ±
, θ =
… (2)
Hence the points are (r cos θ , r sin θ ) where r, θ are given by (1) and (2). Thus we get the four points given in , , , .
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