Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The slope of the tangent to the curve (y – x 5 ) 2 = x(1 + x 2 ) 2 at the point (1, 3) is
Text Solution
Verified by ExpertsThe correct answer is:
8
(8)(y – x 5 ) 2 = x(1 + x 2 ) 2
2(y – x 5 )
= (1 + x 2 ) 2 + 2x (1 + x 2 ) 2x
at point (1, 3)
∴ 2(3 – 1)
= 4 + 8
=
= 3
= 8
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For the function f(x) = x cos , x ≥ 1,
Let p(x) be a polynomial of degree 4 having extremum at x = 1, 2 and = 2. Then the value of p(2) …
Let f be a function defined on R (the set of all real numbers) such that
f ′ (x) = 2010 (x – 2009) …
Let f, g and h be real-valued functions defined on the interval [0, 1] by f(x) = + , g(x) = + …
Match the statements given in Column-I with the intervals/union of intervals given in Column-II
Col…
The number of distinct real roots of x 4 – 4x 3 + 12x 2 + x – 1 = 0 is